The mass of 40 dm ^ 3 of a gas mixture consisting of CO2 and CO is 60 g. Calculate the mass of CO2 in this mixture.

Given:
mixture (CO2, CO)
V mixture = 40 dm ^ 3
m mixture = 60 g

To find:
m (CO2) -?

Decision:
1) V mixture = 40 dm ^ 3 = 40 l;

2) Take the mass of CO2 in the mixture as (x) g, then
m (CO2) = x g;
m (CO) = m mixture – m (CO2) = (60th) g;

3) Find the amount of substance CO2 and CO:
n (CO2) = m (CO2) / Mr (CO2) = (x / 44) mol;
n (CO) = m (CO) / Mr (CO) = (60’s) / 28 mol;

4) Draw up and solve the equation according to the formula for finding the volume of gas:
V mixture = V (CO2) + V (CO);
V (CO2) = n (CO2) * Vm;
V (CO) = n (CO) * Vm;
V of the mixture = n (CO2) * Vm + n (CO) * Vm = (n (CO2) + n (CO)) * Vm;
40 = ((x / 44) + ((60-x) / 28)) * 22.4;
(28x + 2640 – 44x) / 1232 = 40 / 22.4;
28x + 2640 – 44x = 2200;
16x = 440;
x = 27.5;

m (CO2) = x = 27.5 g.

Answer: The mass of CO2 in the mixture is 27.5 g.