The mass of a 22% formic acid solution required to neutralize 150 grams of sodium hydroxide is equal to ..

Let’s write the reaction equation:

HCOOH + NaOH = HCOONa + H2O

Find the amount of sodium hydroxide:

n (NaOH) = m (NaOH) / M (NaOH) = 150 g / 40 g / mol = 3.75 mol

Find the amount of formic acid:

n (HCOOH) = n (NaOH) = 3.75 mol

Find the mass of formic acid:

m (HCOOH) = n (HCOOH) * M (HCOOH) = 3.75 mol * 46 g / mol = 172.5 g

Find the mass of the formic acid solution:

m (r-ra) = (m (r.v.) * 100%) / w (r.v.) = (172.5 g * 100%) / 22% = 784.1 g

Answer: 784.1 g