The mass of a piece of ice is 500 g, and the temperature is 0 ° C. How much heat is required

The mass of a piece of ice is 500 g, and the temperature is 0 ° C. How much heat is required to melt the ice and bring the resulting water to a boil?

Given:

m = 500 grams = 0.5 kilograms – mass of a piece of ice;

T1 = 0 degrees Celsius – the temperature of the ice block;

T2 = 100 degrees Celsius – boiling point of water;

q = 3.4 * 10 ^ 5 J / kg – specific heat of ice melting;

c = 4200 J / (kg * C) – specific heat of water.

It is required to determine the amount of energy Q (Joule) required to melt the ice and heat the resulting water then boiling.

Q = Qmelting + Qheating = q * m + c * m * (T2 – T1) = 3.4 * 10 ^ 5 * 0.5 + 4200 * 0.5 * (100 – 0) =

= 1.7 * 10 ^ 5 + 4200 * 0.5 * 100 = 1.7 * 10 ^ 5 + 210,000 = 1.7 * 10 ^ 5 + 2.1 * 10 ^ 5 = 3.8 * 10 ^ 5 Joules (380 kJ).

Answer: you will need to spend energy equal to 380 kJ.