The mass of aluminum reacted with hydrochloric acid if 6.02-10 ^ 23 hydrogen atoms are obtained.

Metallic aluminum interacts with hydrochloric acid. In this case, an aluminum chloride salt is formed and elemental hydrogen is released. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of the evolved hydrogen gas.

One mole of a substance contains 6.022 x 1023 molecules. A hydrogen molecule consists of 2 hydrogen atoms. Consequently, 0.5 mol of hydrogen was released.

To obtain such an amount of aluminum, it is required to dissolve 0.5 x 2/3 = 0.333 mol of aluminum.

Let’s calculate its mass.

M Al = 27 grams / mol;

m Al = 27 x 0.1666 = 9 grams;