# The mass of bromine interacting with ethylene 140 according to the reaction equation.

January 31, 2021 | education

| According to the condition of the problem, we write the equation:

Н2С = СН2 + Br2 = CH2Br – CH2Br – addition reaction, dibromoethane was obtained;

1 mol 1 mol;

Let’s make calculations using the formulas:

M (C2H4) = 28 g / mol;

M (Br2) = 159.8 g / mol;

Determine the amount of moles of ethylene by the formula:

Y (C2H4) = m / M = 140/28 = 5 mol;

In the equation, the amount of moles of ethylene and bromine is 1 mole, which means that Y (Br2) = 5 moles;

Let’s calculate the mass:

m (Br2) = Y * M = 5 * 159.8 = 799 g.

Answer: bromine is required for the reaction, its mass is exactly 799 g.

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