The mass of calcium required to interact with 11.2 liters of oxygen is?

Calcium enters into an oxidation reaction with oxygen. This reaction is described by the following equation:

Ca + ½ O2 = CaO;

When the reaction proceeds, one oxygen atom is attached to the calcium atom. In this case, one molecule of calcium oxide is synthesized.

Let’s determine the chemical (molar) amount of oxygen.

Divide the available volume of gaseous oxygen by the volume of 1 mole of gas (22.4 liters).

N O2 = 11.2 / 22.4 = 0.5 mol;

In this reaction, 2 times more calcium will react with oxygen.

Let’s find its mass.

N Ca = 0.5 x 2 = 1 mol; M Ca = 40 grams / mol; m Ca = 1 x 40 = 40 grams;