The mass of carbon monoxide (IV) obtained by combustion of 0.1 mol of methane (CH4).

СН4 + 2О2 = СО2 + Н2О + Q – combustion of methane, heat is released, carbon monoxide (4), water;
In accordance with the condition Y (CH4) = 0.1 mol, Y (CO2) = 0.1 mol, since the amount of substances is 1 mol.
M (CO2) = 44 g / mol.

Find the mass of the product:
m (CO2) = Y * M = 0.1 * 44 = 4.4 g

Answer: the product of the combustion reaction, carbon dioxide, weighing 4.4 g was obtained.