The mass of ethyl alcohol, which can be obtained by hydration of 0.7 mol of ethylene, is …

To solve the problem, we write down the equation of the process:

Н2С = СН2 + Н2О = Н3С – СН2 – ОН (С2Н5ОН) – hydration, ethyl alcohol was formed;
Y (C2H4) = 0.7 mol;
Y (C2H5OH) = 0.7 mol since the amount of substances is 1 mol.

Find the mass of the product:
m (C2H5OH) = Y * M = 0.7 * 46 = 32.2 g.

Answer: Ethanol with a mass of 32.2 g was obtained.



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