The mass of oxygen required for complete combustion of 896 ml of ammonia is …

The reaction of non-catalytic oxidation of ammonia with oxygen is described by the following chemical reaction equation:

4NH3 + 3O2 = 2N2 + 6H20;

Let’s calculate the chemical amount of a substance in 0.896 liters of ammonia.

To do this, we divide its volume by the volume of 1 mole of gas (which is 22.4 liters).

N NH3 = 0.896 / 22.4 = 0.04 mol;

To oxidize such an amount of a substance, it is necessary to take (in accordance with the coefficients of the chemical equation) 0.04 x 3/4 = 0.03 mol of oxygen.

Determine the weight of oxygen.

To do this, multiply its amount by the mass of 1 mole of oxygen.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 0.03 x 32 = 0.96 grams;