The mass of silicic acid that can theoretically be obtained by reacting with hydrochloric acid 15.25 g of sodium silicate containing 20% impurities will be …
When sodium silicate and hydrochloric acid interact, the following chemical reaction occurs:
Na2SiO3 + 2HCl = 2NaCl + H2SiO3;
Let’s find the chemical amount of sodium silicate:
For this purpose, we divide its weight by the mass of 1 mole of the substance.
M Na2SiO3 = 23 x 2 + 28 + 16 x 3 = 122 grams / mol;
n Na2SiO3 = 15.25 / 122 = 0.125 mol;
The same amount of silicic acid can be obtained.
Let’s calculate its weight.
To do this, we multiply the amount of the substance by its molar weight.
M H2SiO3 = 2 + 28 + 16 x 3 = 78 grams / mol;
m H2SiO3 = 0.125 x 78 = 9.75 grams;
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