The mass of silver nitrate required for the preparation of 350 g of a 6% solution.

Find the weight of the dissolved salt.

M salt = 350 x 0.06 = 21 grams;

In the same way we find the weight of the solvent (water).

(In the calculations, we take the density of water equal to 1 gram / cm3).

M water = 350 x 0.94 = 329 grams = 329 ml;

Let’s check. To do this, add the masses of the components of the solution and get the weight of the solution in question.

21 + 329 = 350;