The mass of sodium chloride obtained in the interaction of 80 g of NAOH C 109.5 g of HCL

NaOH + HCl = NaCl + H2O – ion exchange, table salt (sodium chloride;
Calculations:
M (NaOH) = 39.9 g / mol;

M (HCl) = 36.5 g / mol

M (NaCl) = 58.4 g / mol.

Let’s determine the amount of starting materials:
Y (NaOH) = m / M = 80 / 39.9 = 2 mol (deficient substance);

Y (HCl) = m / M = 109.5 / 36.5 = 3 mol (substance in excess);

Y (NaCl) = 2 mol since the amount of substances is 1 mol.

Calculations are carried out taking into account the substance in deficiency.

Find the mass of the product:
m (NaCl) = Y * M = 2 * 58.4 = 116.8 g

Answer: the mass of sodium chloride is 116.8 g