# The mass of sodium sulfate solution is 284 grams. mass fraction 10%. an excess of barium chloride

January 17, 2021 | education

| **The mass of sodium sulfate solution is 284 grams. mass fraction 10%. an excess of barium chloride was added to the solution. Find the mass of the sediment.**

Given:

m solution (Na2SO4) = 284 g

w (Na2SO4) = 10% = 0.1

To find:

m (BaSO4)

Decision:

Na2SO4 + BaCl2 = BaSO4 + 2NaCl

m in-va (Na2SO4) = w * m solution = 0.1 * 284 g = 28.4 g

n (Na2SO4) = m / M = 284 g / 142 g / mol = 2 mol

n (Na2SO4): n (BaSO4) = 1: 1

n (BaSO4) = 2 mol

m (BaSO4) = n * M = 2 mol * 233 g / mol = 466 g

Answer: 466 g

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