The mass of sodium sulfate solution is 284 grams. mass fraction 10%. an excess of barium chloride

The mass of sodium sulfate solution is 284 grams. mass fraction 10%. an excess of barium chloride was added to the solution. Find the mass of the sediment.

Given:
m solution (Na2SO4) = 284 g
w (Na2SO4) = 10% = 0.1
To find:
m (BaSO4)
Decision:
Na2SO4 + BaCl2 = BaSO4 + 2NaCl
m in-va (Na2SO4) = w * m solution = 0.1 * 284 g = 28.4 g
n (Na2SO4) = m / M = 284 g / 142 g / mol = 2 mol
n (Na2SO4): n (BaSO4) = 1: 1
n (BaSO4) = 2 mol
m (BaSO4) = n * M = 2 mol * 233 g / mol = 466 g
Answer: 466 g