The mass of sulfur is 32 grams, the yield is 80% of the theoretical find sulfur oxide (4).

S + O2 = SO2
n (S) = m (S) / M (S)
n (S) = 32g / 32 g / mol = 1 mol
n (SO2) = n (S) = 1 mol
m (SO2) = 1 * 64 = 64 g
M (SO2) = 64g / mol
0.8 = mpract. / m theor.
mp = 0.8 * 64 = 51.2 g



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