The mass of table salt (in grams) in a solution with a volume of 1 liter with a mass fraction of salt of 8%

The mass of table salt (in grams) in a solution with a volume of 1 liter with a mass fraction of salt of 8% and a density of 1.05 g / cm3 is equal to

Given:
V solution (NaCl) = 1 l = 1000 ml
ω (NaCl) = 8%
ρ solution (NaCl) = 1.05 g / cm3 = 1.05 g / ml

To find:
m (NaCl) -?

Decision:
1) m solution (NaCl) = ρ solution * V solution = 1.05 * 1000 = 1050 g;
2) m (NaCl) = ω * m solution / 100% = 8% * 1050/100% = 84 g.

Answer: The mass of NaCl is 84 g