The mass of the first body is 2 kg, its speed is 6 m / s. The second body is at rest. After an inelastic collision
The mass of the first body is 2 kg, its speed is 6 m / s. The second body is at rest. After an inelastic collision, both bodies move at the same speed equal to 2 m / s. Second body weight.
Given:
m1 = 2 kilograms – the mass of the first body;
v1 = 6 meters / second – the speed of movement of the first body;
v = 2 meters / second – the speed of movement of two bodies after an inelastic collision.
It is required to determine m2 (kilogram) – the mass of the second body.
Since, according to the condition of the problem, the second body was at rest at the moment of collision, then in order to determine the mass of the second body, it is necessary to use the following expression (the law of conservation of momentum):
m1 * v1 = (m1 + m2) * v;
m1 * v1 = m1 * v + m2 * v;
m2 * v = m1 * v1 – m1 * v;
m2 * v = m1 * (v1 – v);
m2 = m1 * (v1 – v) / v;
m2 = 2 * (6 – 2) / 2 = 2 * 4/2 = 8/2 = 4 kilograms.
Answer: the mass of the second body is 4 kilograms.