The mass of the precipitate formed as a result of the interaction of 5.2 g of barium chloride with an acid solution in excess is …

univerkov | January 17, 2021 | education

Given:
m (BaCl2) = 5.2 g
To find:
m (BaSO4)
Decision:
BaCl2 + H2SO4 = BaSO4 + 2HCl
n (BaCl2) = m / M = 5.2 g / 208 g / mol = 0.025 mol
n (BaCl2): n (BaSO4) = 1: 1
n (BaSO4) = 0.025 mol
m (BaSO4) = n * M = 0.025 mol * 233 g / mol = 5.825 g
Answer: 5.825 g

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