1. Let’s compose the reaction equation:
CaO + H2CO3 = CaCO3 + H2O;
2.determine the chemical quantities of the interacting substances:
n (CaO) = m (CaO): M (caO);
M (CaO) = 40 + 16 = 56 g / mol;
n (CaO) = 11.2: 56 = 0.2 mol;
n (H2CO3) = m (H2CO3): M (H2CO3);
M (H2CO3) = 2 + 12 + 3 * 16 = 62 g / mol;
n (H2CO3) = 12.4: 62 = 0.2 mol;
3. Determine the mass of the resulting sediment:
n (CaCO3) = n (H2CO3) = 0.2 mol;
m (CaCO3) = n (CaCO3) * M (CaCO3);
M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;
m (CaCO3) = 0.2 * 100 = 20 g.
Answer: 20 g.
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