The mass of the sediment obtained by the interaction of 11.2 calcium oxide with 12.4 carbonic acid

1. Let’s compose the reaction equation:

CaO + H2CO3 = CaCO3 + H2O;

2.determine the chemical quantities of the interacting substances:

n (CaO) = m (CaO): M (caO);

M (CaO) = 40 + 16 = 56 g / mol;

n (CaO) = 11.2: 56 = 0.2 mol;

n (H2CO3) = m (H2CO3): M (H2CO3);

M (H2CO3) = 2 + 12 + 3 * 16 = 62 g / mol;

n (H2CO3) = 12.4: 62 = 0.2 mol;

3. Determine the mass of the resulting sediment:

n (CaCO3) = n (H2CO3) = 0.2 mol;

m (CaCO3) = n (CaCO3) * M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

m (CaCO3) = 0.2 * 100 = 20 g.

Answer: 20 g.