The mass of water (g) required for the preparation of 250 g of a solution with a mass fraction

The mass of water (g) required for the preparation of 250 g of a solution with a mass fraction of sulfuric acid of 20% is …

Let’s calculate the masses of the components of the solution.

To do this, it is necessary to multiply their mass fraction by the weight of the solution.

Determine the weight of pure sulfuric acid.

M pure acid = 250 x 0.2 = 50 grams;

In the same way, we find the mass of water.

(In the calculations, we will make the assumption that the density of water is 1 gram / ml).

M water (solvent) = 250 x 0.8 = 200 grams = 200 ml;

Let’s check:

M solution = M acid + M water = 50 + 200 = 250 grams;