The mass of zinc, which interacts with an excess of sulfuric acid solution, if 10 g of hydrogen

The mass of zinc, which interacts with an excess of sulfuric acid solution, if 10 g of hydrogen is released as a result of the reaction, is equal to… g.

Given:
m (H2) = 10 g
To find:
m (Zn)
Decision:
Zn + H2SO4 = ZnSO4 + H2
n (H2) = m / M = 10 g / 2 g / mol = 5 mol
n (H2): n (Zn) = 1: 1
n (Zn) = 5 mol
m (Zn) = n * M = 5 mol * 65 g / mol = 325 g
Answer: 325 g