# The maximum charge on the plates of the capacitor of the oscillatory circuit is 1 μC. The amplitude value

The maximum charge on the plates of the capacitor of the oscillatory circuit is 1 μC. The amplitude value of the electric current in the circuit is 2mA. Determine the period of oscillation.

Given:
q = 1 μC;
I = 2 mA.
Find: T.
Decision:
Let’s write down the proportion. We need it in order to find how the product LC is expressed, since we need this to find the answer through the period search formula.
L * Im ^ 2/2 = qm ^ 2 / 2C.
Let us express LC from here.
L * C = qm ^ 2 / Im ^ 2.
Next, we write down the formula for finding the period:
T = 2 * pi * sqrt (L * C)
Now you can replace (LC) with the expression we found above, then substitute the known values and therefore get the answer.
T = 2 * pi * root of qm ^ 2 / Im ^ 2 = 2pi * am / lm = 6.28 * 10 ^ -6 / 2 * 10 ^ -3 = 3.14 * 10 ^ -3 c.
Answer: 3.14 * 10 ^ -3

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