The maximum data transfer rate for the modem is 4096 bps.

The maximum data transfer rate for the modem is 4096 bps. It took 10 seconds to transfer the file over this connection. Determine the file size in KB.

Given: baud rate: 4096 bps; data transfer time: 10 s.

Decision:

1. Determine the size of the transmitted file in bits: 4096 * 10 = 40960 bits.

2. Let’s convert the file size into bytes. To do this, you need to know that 1 byte = 8 bits.

40960 bits = 40960/8 = 5120 bytes.

3. Let’s convert the file size to kilobytes. To do this, you need to know that

1 kilobyte = 1024 bytes.

5120 bytes = 5120/1024 = 5 kilobytes.

Answer: The size of the transferred file is 5 kilobytes.