The maximum tension of the dynamometer spring, equal to 4 cm, occurs under the action of a force equal to 800 N.
| November 16, 2020 | education
The maximum tension of the dynamometer spring, equal to 4 cm, occurs under the action of a force equal to 800 N. How much will the spring stretch under the action of a force of 100 N; 300H
F = kx (Hooke’s law where K is the spring rate and x is the amplitude). 800n = K * 4 K = 200 F = KX -> X = F / K 1.X = 100/200 = 0.5 cm 2.X = 300/200 = 1.5cm Answer: 0.5 cm; 1.5 cm.
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