The median BM ABC is perpendicular to its BP bisector. Find AB (in cm) if AC = 15 cm.

1) O-point of intersection of AK and BM. 2) Triangles ABO and ABO are equal, because AO-common leg 3) Angles at O are equal to 90 degrees. and angle BAO = angle OAM (since AO is the bisector). => AK = AM AM = 7.5 (since M is the middle of the AU).
Answer AK = 7.5.



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