The median BM is drawn in triangle ABC and BM = AB. BMC = 108. Then BAM is.

The BM median in ∆ABC forms two adjacent angles with the AC side: ∠BMC and ∠BMA.

Adjacent corners are corners that have one side in common and the other two are complementary rays.

The sum of adjacent angles theorem says that the sum of adjacent angles is 180 °.

Then ∠BMC + ∠BMA = 180 °. So we can find ∠BMA.

∠BMA = 180 ° – ∠BMC = 180 ° – 108 ° = 72 °.

Consider ∆BMA.

In ∆BMA side AB = BM by condition, then ∆BMA is isosceles.

In an isosceles triangle, the angles at the base are equal, therefore, ∠BAM = ∠BMA = 72 °.

Answer: ∠BAM = 72 °.