The median CD of triangle ABC is 9 cm. Find the segments CO and OD where point O

The median CD of triangle ABC is 9 cm. Find the segments CO and OD where point O is the intersection point of the median of triangle ABC.

The median of a triangle is the segment that connects the apex of the triangle to the middle of the opposite side.

The main property of medians: the medians of a triangle intersect at one point, and are divided by this point into two parts in a ratio of 2: 1, counting from the vertex.

Given: triangle ABC, CD is the median of the triangle, CD = 9 cm, point O is the point of intersection of the medians.

Find: CO and OD.

Solution: point O is the point of intersection of the medians, which means that it divides the CD into two parts CO: OD = 2: 1; CO = 9: 3 * 2 = 6 (cm), OD = 9: 3 * 1 = 3 (cm).

Answer: SB = 6 cm; OD = 3 cm.



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