The median CD of triangle ABC is 9 cm. Find the segments CO and OD where point O
The median CD of triangle ABC is 9 cm. Find the segments CO and OD where point O is the intersection point of the median of triangle ABC.
The median of a triangle is the segment that connects the apex of the triangle to the middle of the opposite side.
The main property of medians: the medians of a triangle intersect at one point, and are divided by this point into two parts in a ratio of 2: 1, counting from the vertex.
Given: triangle ABC, CD is the median of the triangle, CD = 9 cm, point O is the point of intersection of the medians.
Find: CO and OD.
Solution: point O is the point of intersection of the medians, which means that it divides the CD into two parts CO: OD = 2: 1; CO = 9: 3 * 2 = 6 (cm), OD = 9: 3 * 1 = 3 (cm).
Answer: SB = 6 cm; OD = 3 cm.