The message occupies 2 pages and contains 1 / 16Kbyte of information

The message occupies 2 pages and contains 1 / 16Kbyte of information, each page contains 256 characters as one letter carries the amount of information.

Let us denote by the letter I the informational volume of the message, by the letter n – the number of characters, i – the weight of one character (the number of bits for encoding one character), N – the power of the alphabet.

Given:

I = 1/16 KB;

n = 2 * 256 = 512;

Find: i -?

Decision:

1) First, let’s translate the amount of information into bits:

1 KB = 1024 bytes = 8192 bits;

1/16 KB = 8192 bits / 16 = 512 bits.

2) Divide the total amount of information by the number of characters to get the weight of one character:

i = I / n;

i = 512 bits / 512 = 1 bit;

Answer: one letter carries 1 bit of information