The metal ball A, which lacks 1.4 * 10 (to the 12th power) electrons, touched the same

| July 5, 2021 | education

The metal ball A, which lacks 1.4 * 10 (to the 12th power) electrons, touched the same, but non-electrified ball B. What will be the charge of the ball B after it moves away from the ball A?

n = 1.4 * 10 ^ 12.

q = 1.6 * 10 ^ 6-19 Cl.

Q1 -?

Free electrons are charge carriers in metals. When a charged and a neutral metal ball touches, as a result of electrification through contact, free electrons will begin to transfer to a positively charged ball. This transition will be carried out until the charges of the balls are the same. That is, only half of the missing electrons will be able to transfer from the neutral ball to the ball on which there were not enough electrons: n1 = n / 2.

Each electron carries an elementary charge q = 1.6 * 10 ^ -19 C.

Q1 = n1 * q = n * q / 2.

Q1 = 1.4 * 10 ^ 12 * 1.6 * 10 ^ -19 C / 2 = 1.12 * 10 ^ -7 C.

Answer: the charge of balls A and B after contact will become Q1 = 1.12 * 10 ^ -7 C.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.