The mica condenser consists of two plates with an area of 15 cm ^ 2 each. The distance between the plates is 0.2 mm.

The mica condenser consists of two plates with an area of 15 cm ^ 2 each. The distance between the plates is 0.2 mm. What is the greatest charge that can be imparted to a capacitor at a voltage of 2 * 10 ^ 3 V?

Given: S (plate area) = 15 cm2 (in SI S = 15 * 10-4 m); d (distance between plates) = 0.2 mm (in SI d = 0.2 * 10-3 mm); U (voltage) = 2 * 103 V.

Constants: ε (relative dielectric constant of mica) = 5.7 … 11.5 (we take 8.6); ε0 (electrical constant) = 8.85 * 10-12 F / m.

The largest charge that can be imparted to the taken mica capacitor: q = U * C = U * ε * ε0 * S / d.

Calculation: q = 2 * 103 * 8.6 * 8.85 * 10-12 * 15 * 10-4 / (0.2 * 10-3) ≈ 1.14 * 10-6 C (1.14 μC) …