The middle line DF (DF || AC) is drawn in triangle ABC. perimeter (DBF) = 1.8 dm Calculate the perimeter of triangle ABC.

Perimeter of triangle DBF:

P = DB + BF + DF;

Perimeter of triangle ABC:

P ‘= AB + BC + AC;

Since DF is the middle line, then

AD = DB; AB = 2 * DB;

BF = FC; BC = 2 * FC;

DF = 1/2 AC; AC = 2 * DF;

All sides of triangle ABC are twice the sides of triangle DBF, which means

P ‘= 2 * P = 2 * 1.8 = 3.6 (dm).



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