The middle line of the trapezoid meets the diagonal and is divided by 7 and 13 cm. Find the base of the trapezoid.

Consider a triangle ABC, in which the segment MO is its middle line, since MO is parallel to BC and point M is the middle of side AB.

The midline of a triangle is half the length of a side parallel to the midline.

MO = BC / 2.

BC = MO * 2 = 7 * 2 = 14 cm.

Similarly, in the AСD triangle, segment НO, the middle line of the triangle, then  AD= 2 * HO = 2 * 13 = 26 cm.

Answer: The bases of the trapezoid are 14 cm and 26 cm.



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