The middle lines of the triangle are 5 cm, 7 cm and 12 cm. Find the perimeter of this triangle.

The middle lines of a triangle connect the midpoints of the sides of the triangle, they are equal to half the length of the sides to which they are parallel:

AB = HM · 2;

AB = 5 2 = 10 cm;

BC = KM · 2;

BC = 7 2 = 14 cm;

AC = KH · 2;

AC = 12 2 = 24 cm.

The perimeter of a triangle is the sum of the lengths of all its sides:

P = AB + BC + AC;

P = 10 + 14 + 24 = 48 cm.

Answer: the perimeter of the triangle, the middle lines of which are 5 cm, 7 cm and 12 cm, is 48 cm.



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