The midline of an isosceles trapezoid is 5 cm, the lateral side is 4 cm
| May 25, 2021 | education
The midline of an isosceles trapezoid is 5 cm, the lateral side is 4 cm, inclined to the base at an angle of 30 degrees. Find the area of the trapezoid.
In a right-angled triangle ABH, the BH leg lies opposite the angle 30, therefore, its length is equal to half the length of the hypotenuse AB. BH = AB / 2 = 4/2 = 2 cm.
Since the middle line of the trapezoid is equal to half the sum of the lengths of the bases of the trapezoid, then the area of the trapezoid will be equal to:
Savsd = (BC + AD) * BH / 2 = KM * BH = 5 * 2 = 10 cm2.
Answer: The area of the trapezoid is 10 cm2.
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