The midline of the trapezoid is 20 and the smaller base is 10. Find the larger base of the trapezoid.

Given:
ABCD – trapezoid;
EF – cf. line;
EF = 20;
AD and BC – bases;
BC = 10;
AD =?
Decision:
The middle line of the trapezoid is equal to half the sum of the bases.
EF = 1/2 * (AD + BC);
AD + BC = 2 * EF;
AD = 2 * EF-BC;
Substitute the corresponding values. Then:
AD = 2 * 20-10 = 40-10 = 30
Answer: 30



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