The midpoint of the minute hand of the watch is at a distance of 2 cm from the center of the dial. determine the path

The midpoint of the minute hand of the watch is at a distance of 2 cm from the center of the dial. determine the path L and the displacement s of this point by 30 minutes if it covers a path equal to 12.56 cm in an hour

In an hour, the hand travels 12.56 cm.Since the hand moves in a circle, then:
S = 2пR
Let’s substitute:
12.56 = 2 * 3.14 * 2
12.56 = 6.28 * 2
12.56 = 12.56
Everything is correct. And since the arrow moves evenly, then if in an hour it has passed 12.56 cm, then in half an hour it will pass 12.56 / 2 = 6.28 cm.
Now let’s find the displacement:
In half an hour, the arrow will describe a semicircle. So if you connect the start and end positions, you get the diameter.
Since radius = 2cm, then diameter = 2 * 2 = 4cm
Answer: L = 6.28; S = 4