The mine is 200 m deep, at the surface the atmospheric pressure is 752 mm Hg. Art.

The mine is 200 m deep, at the surface the atmospheric pressure is 752 mm Hg. Art. Find the pressure at the bottom of the shaft.

As you know, with an increase in depth by 10 meters, atmospheric pressure will increase by 1 mm Hg.

In this case, since the depth of the mine is 200 meters, the difference between the atmospheric pressure on the surface and in the mine will be:

200/10 = 20 mm Hg

Find the pressure in the mine.

To do this, add the found pressure difference to the indicated atmospheric pressure on the surface.

Will:

752 + 20 = 772 mm Hg

Answer:

The pressure at the bottom of the mine will be 772 mm Hg.