The modem can transmit a raster graphic image of 480 * 512 pixels in a 256-color palette within
The modem can transmit a raster graphic image of 480 * 512 pixels in a 256-color palette within 1 minute. Determine the baud rate.
1) Find the total number of pixels in the graphic image.
We multiply its sizes among ourselves.
480 * 512 = 245760 pixels.
2) Determine the information volume of one pixel.
For this we use the following formula:
N = 2 ^ i
256 = 2 ^ 8
i = 8 bits (there are 8 bits of information in 1 pixel).
We find the information volume of the image.
Multiply the total number of pixels by 8 bits.
245760 * 8 = 1966080 bits.
We translate the amount of information into bytes.
1966080/8 = 245760.
We translate the transmission time from minutes to seconds.
1 minute = 60 seconds
Find the transmission speed.
We divide the volume of the image by the time of transmission.
245760/60 = 4096 bytes per second.
Answer: 4096 bytes / s.