# The modem can transmit a raster graphic image of 480 * 512 pixels in a 256-color palette within

**The modem can transmit a raster graphic image of 480 * 512 pixels in a 256-color palette within 1 minute. Determine the baud rate.**

1) Find the total number of pixels in the graphic image.

We multiply its sizes among ourselves.

480 * 512 = 245760 pixels.

2) Determine the information volume of one pixel.

For this we use the following formula:

N = 2 ^ i

256 = 2 ^ 8

i = 8 bits (there are 8 bits of information in 1 pixel).

We find the information volume of the image.

Multiply the total number of pixels by 8 bits.

245760 * 8 = 1966080 bits.

We translate the amount of information into bytes.

1966080/8 = 245760.

We translate the transmission time from minutes to seconds.

1 minute = 60 seconds

Find the transmission speed.

We divide the volume of the image by the time of transmission.

245760/60 = 4096 bytes per second.

Answer: 4096 bytes / s.