The modulus of maximum acceleration with which the elevator can move is 0.6 m / s. The weight of the lift is 5 tons.

The modulus of maximum acceleration with which the elevator can move is 0.6 m / s. The weight of the lift is 5 tons. To what extent will the tension force of the cable change during the movement of the elevator?

Given:
a = 0.6 m / s2 – modulus of maximum acceleration with which the elevator can move;
g = 9.8 Newton / kilogram – acceleration of gravity;
m = 5 tons = 5000 kilograms – the mass of the lift.
It is required to determine within what limits the tension force of the cable will change during the movement of the elevator.
Find the minimum cable tension (when the lift moves down):
T + m * a = m * g;
T = m * g – m * a = m * (g – a) = 5000 * (9.8 – 0.6) = 5000 * 9.2 = 46000 Newtons.
Let’s find the maximum pulling force of the cable (when the elevator moves up):
T = m * g + m * a = m * (g + a) = 5000 * (9.8 + 0.6) = 5000 * 10.4 = 52000 Newtons.
That is, 46000 <T <52000.
Answer: The tension of the thread will vary from 46000 Newtons to 52000 Newtons.