# The modulus of the force of the gravitational interaction of two point bodies located at a distance of three meters

**The modulus of the force of the gravitational interaction of two point bodies located at a distance of three meters from each other is 5 N. What will be the modulus of the force of the gravitational interaction of these bodies if the distance between them is reduced by 1 m?**

The force of gravitational interaction can be calculated by the formula:

F = G * m1 * m2 / r ^ 2, where G is the gravitational constant, m1, m2 are the masses of bodies, r is the distance between bodies.

For a distance of 3 m:

F1 = G * m1 * m2 / r1 ^ 2 = G * m1 * m2 / 3 ^ 2 = G * m1 * m2 / 9.

Since F1 = 5 N, then G * m1 * m2 = 9 * F1 = 9 * 5 = 45.

For a distance of 2 m (the initial distance is reduced by 1 m):

F2 = G * m1 * m2 / r2 ^ 2 = G * m1 * m2 / 2 ^ 2 = G * m1 * m2 / 4 = 45/4 = 11.25 N.

Answer: The force of gravitational interaction is 11.25 N.