# The modulus of the force of the gravitational interaction of two point bodies located at a distance of three meters

The modulus of the force of the gravitational interaction of two point bodies located at a distance of three meters from each other is 5 N. What will be the modulus of the force of the gravitational interaction of these bodies if the distance between them is reduced by 1 m?

The force of gravitational interaction can be calculated by the formula:
F = G * m1 * m2 / r ^ 2, where G is the gravitational constant, m1, m2 are the masses of bodies, r is the distance between bodies.
For a distance of 3 m:
F1 = G * m1 * m2 / r1 ^ 2 = G * m1 * m2 / 3 ^ 2 = G * m1 * m2 / 9.
Since F1 = 5 N, then G * m1 * m2 = 9 * F1 = 9 * 5 = 45.
For a distance of 2 m (the initial distance is reduced by 1 m):
F2 = G * m1 * m2 / r2 ^ 2 = G * m1 * m2 / 2 ^ 2 = G * m1 * m2 / 4 = 45/4 = 11.25 N.
Answer: The force of gravitational interaction is 11.25 N. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.