The molar mass of the gas is 44 * 10-3 kg / mol. What is the density of this gas at a temperature of 300 K
The molar mass of the gas is 44 * 10-3 kg / mol. What is the density of this gas at a temperature of 300 K and a pressure of 10 ^ 5 Pa?
M = 44 * 10-3 kg / mol.
P = 105 Pa.
T = 300 ° K.
R = 8.31 m2 * kg / s2 * ° K * mol.
ρ -?
The density of a substance ρ is the ratio of its mass m to the volume V it occupies: ρ = m / V.
For gas, the Mendeleev-Cliperon equation is valid, which is determined by the formula: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature gas, M is the molar mass of the gas.
Let us express the ratio of the gas mass m to its volume V, which is the gas density ρ: ρ = m / V = P * M / R * T.
ρ = 105 Pa * 44 * 10: -3 kg / mol / 8.31 m2 * kg / s2 * ° K * mol * 300 ° K = 1.765 kg / m3.
Answer: the density of the gas is ρ = 1.765 kg / m3.