The molecular formula of a hydrocarbon with a relative oxygen density of 1.75 and a mass

The molecular formula of a hydrocarbon with a relative oxygen density of 1.75 and a mass fraction of hydrogen of 14.3% is …

1. Let’s find the molecular weight of the hydrocarbon:

32 * 1.75 = 56 g / mol;

2. Let’s find the mass of hydrogen in the substance:

56 * 0.143 = 8 g / mol;

A hydrocarbon contains 8 hydrogen atoms.

3. Find the mass of carbon in the hydrocarbon:

56 – 8 = 48 g / mol;

4. Find the number of carbon atoms:

48/12 = 4 atoms;

Answer: The molecular formula of the hydrocarbon is C4H8.