The moment of force acting on the lever is 20 N⋅m. What should be the shoulder

The moment of force acting on the lever is 20 N⋅m. What should be the shoulder of the second force for the lever to be in equilibrium if its value is 10 N?

Given:

P1 = 20 Newton * meter – the moment of some force acting on the lever;

F = 10 Newton – the magnitude of the force acting on the opposite end of the lever.

It is required to determine l (meter) – the arm of the force F.

To determine the shoulder of the second force, you need to use the following formula (leverage rule):

P1 = F * l, from here we find that:

l = P1 / F = 20/10 = 2 meters.

Answer: the shoulder of the second force should be 2 meters.