The moped engine consumes 2 kg of gasoline. How much heat is emitted during the combustion of gasoline.

Initial data: m (consumed mass of gasoline) = 2 kg.

Constants: q (specific heat of combustion of gasoline) = 4.6 * 10 ^ 7 J / kg.

The amount of heat released during the combustion of 2 kg of gasoline is calculated using the formula:

Q = q * m = 4.6 * 10 ^ 7 * 2 = 9.2 * 10 ^ 7 J = 92 * 10 ^ 6 J = 92 MJ.

Answer: When 2 kg of gasoline is burned, 92 MJ of heat is released.



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