The motor ship goes along the river to its destination 483 km and after stopping it returns to the point

The motor ship goes along the river to its destination 483 km and after stopping it returns to the point of departure. Find the speed of the current, if the speed of the ship in still water is 22 km / h, the stay lasts 2 hours, and the ship returns to the point of departure 46 hours after departure.

Let the speed of the river flow be x km / h, it is known that the speed of the motor ship in still water is 22 km / h, then the speed along the river will be (22 + x) km / h, and against the river flow (22 – x) km / h hour. Then the time of movement of the motor ship along the river will be 483: (22 + x) hour, and against the course of the river will be 483: (22 – x) hour. Let’s find how long the ship was in motion:
46 – 2 = 44 (hour);
Let’s compose an equation that meets the given condition:
483: (22 + x) + 483: (22 – x) = 44;

483 / (22 + x) + 483 / (22 – x) – 44 = 0;
(483 * (22 – x) + 483 * (22 + x) – 44 (22 + x) (22 – x)) / (22 + x) (22 – x) = 0;
(10626 – 483x + 10626 + 483x – 21296 + 44x ^ 2) / (484 – x ^ 2) = 0;
(-44 + 44x ^ 2) / (484 – x ^ 2) = 0;
-44 + 44x ^ 2 = 0;
44x ^ 2 = 44;
x ^ 2 = 44: 44;
x ^ 2 = 1;
x1 = 1, x2 = -1.
The speed of the river flow cannot be negative, therefore it will be equal to 1 km / h.
Answer: 1 km / h.