The motor ship, sailing at a speed of 32.4 km / h, began to slow down evenly and, approaching

The motor ship, sailing at a speed of 32.4 km / h, began to slow down evenly and, approaching the pier after 36 seconds, completely stopped. What is the ship’s acceleration? what way did he go during the braking time?

To find the acceleration of the motor ship and the distance traveled by it during the braking time, we will use the formulas: a = Vn / t and S = Vn * t / 2.

Values of variables: Vн – initial speed of the ship (Vн = 32.4 km / h = 9 m / s); t is the duration of the deceleration of the motor ship (t = 36 s).

Calculation: a) acceleration of the ship: a = Vn / t = 9/36 = 0.25 m / s2;

b) the route traveled by the motor ship: S = Vн * t / 2 = 9 * 36/2 = 162 m.

Answer: During the braking time, the motor ship covered 162 m, moving with an acceleration of 0.25 m / s2.