The movement of a body weighing 500 g is described by the equation x = 4t ^ 2 + 3t. determine the resulting

The movement of a body weighing 500 g is described by the equation x = 4t ^ 2 + 3t. determine the resulting force acting on the body

x (t) = 4 * t ^ 2 + 3 * t.

m = 500 g = 0.5 kg.

F -?

According to Newton’s 2 law, the resulting force F, which acts on a body, is equal to the product of the body’s mass m by its acceleration a: F = m * a.

With uniformly accelerated motion, the coordinate of the body changes according to the law: x (t) = x0 + V0 * t + a * t ^ 2/2, where x0 is the initial velocity of the body, V0 is the initial velocity of the body, and is the acceleration during uniformly accelerated motion.

For the dependence x (t) = 3 * t + 4 * t ^ 2, the body moves rectilinearly from the initial coordinate x0 = 0 m, with the initial speed of movement V0 = 3 m / s, with the acceleration of motion a = 8 m / s2.

F = 0.5 kg * 8 m / s2 = 4 N.

Answer: the resulting force that acts on the body is F = 4 N.