The movement of a car is given by the equation x = 50 + 30t + 0.6t ^ 2 (all values are in SI units)

The movement of a car is given by the equation x = 50 + 30t + 0.6t ^ 2 (all values are in SI units) What is the value of the resultant force applied to the car? the mass of the car is 1.5 tons.

x (t) = 50 + 30 * t + 0.6 * t ^ 2.

m = 1.5 t = 1500 kg.

F -?

According to 2 Newton’s law, the resultant of all forces F that act on a passenger car is the product of its mass F and acceleration a: F = m * a.

From the dependence of the coordinate on time x (t) = 50 + 30 * t + 0.6 * t ^ 2, we see that the body moves uniformly accelerated from the initial coordinate x0 = 50 m, initial speed V0 = 30 m / s and acceleration a = 1 , 2 m / s2.

F = 1500 kg * 1.2 m / s2 = 1800 N.

Answer: the resultant force F = 1800 N acts on a passenger car.