The movement of a material point is described by the equation x = 2.5-4t + 2t ^ {2} Taking its mass 1kg
April 8, 2021 | education
| The movement of a material point is described by the equation x = 2.5-4t + 2t ^ {2} Taking its mass 1kg, find the impulse in 1s and 2s after the start of the time count, as well as the force, this is a change in impulse.
x = 2.5 – 4 * t + 2 * t ^ 2.
m = 1 kg.
t1 = 1 s.
t2 = 2 s.
p1 -?
p2 -?
F -?
V (t) = x (t) “.
V (t) = (2.5 – 4 * t + 2 * t ^ 2) “= – 4 + 2 * 2 * t = 4 * t – 4.
V1 = 4 * 1 – 4 = 0 m / s.
V2 = 4 * 2 – 4 = 4 m / s.
p1 = m * V1.
p1 = 1 kg * 0 m / s = 0 kg * m / s.
p2 = m * V2.
p2 = 1 kg * 4 m / s = 4 kg * m / s.
F = (p2 – p1) / (t2 – t1).
F = (4 kg * 4 m / s – 0 kg * m / s) / (2 s – 1 s) = 16 N.
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