The movement of a material point is described by the equation x = 20-10t. Describe the nature of the movement

The movement of a material point is described by the equation x = 20-10t. Describe the nature of the movement, find the starting coordinate of the point, the magnitude and direction of the velocity vector. What is the acceleration of a material point, at what moment in time the coordinate of the point will be equal to 0 m?

x (t) = 20 – 10 * t.

x1 = 0.

t1 -?

x0 -?

V -?

a – ?

1 way.

With uniform rectilinear motion of the body, the dependence of the coordinates of the body on time x (t) has the form: x (t) = х0 + V * t, where х0 is the initial coordinate of the body, V is the speed of uniform movement.

x0 = 20 m, V = – 10 m / s.

The “-” sign indicates that the body is moving in the opposite direction of the OX coordinate axis.

With uniform motion, the acceleration of the body is a = 0 m / s2.

20 – 10 * t1 = 0.

t1 = 2 s.

Answer: x0 = 20 m, the body moves in the opposite direction of the OX coordinate axis with a speed V = 10 m / s, = 0 m / s2, t1 = 2 s.