The movement of a trolleybus during emergency braking is given by the equation x = 30 + 15t-2.5t ^ 2

The movement of a trolleybus during emergency braking is given by the equation x = 30 + 15t-2.5t ^ 2. What is the acceleration of the trolleybus What is the initial speed of the trolleybus What is the initial coordinate of the trolleybus?

Initial data: the equation of motion of a trolleybus during emergency braking x = 30 + 15t – 2.5t ^ 2.

1) Acceleration of the trolleybus: a = S ” = (30 + 15t – 2.5t ^ 2) ” = (0 + 15 * 1 – 2 * 2.5t) ‘= (15 – 5t)’ = 0 – 5 = -5 m / s2 (slow motion).

2) Initial speed of the trolleybus: V0 = S (0) ‘= 15 – 5t = 15 – 5 * 0 = 15 m / s.

3) The initial coordinate of the trolleybus: S (0) = 30 + 15 * 0 – 2.5 * 0 ^ 2 = 30 m.